GEOMETRIC PROGRESSION
A sequence of non-zero numbers is called a geometric progression (G.P.) if the ratio of the term and the term preceding to it is always a constant quantity.
A sequence a1, a2, a3, a4,
………an, an+1 is
called geometric progression.
If
is the common ratio of GP. Where
General Geometric Progression is a, ar, ar2, ar3, ……….., arn-1
First term = a, Second term = ar, and so on and r is the common ratio of GP
nth term in GP is =
arn-1
Sum of first n terms in GP is
}{r-1}\:%20where,%20r%20%3E%201)
Sum of first n terms in GP is
}{1-r}\:%20where,\:%20\:%20r%20%3C%201)
Sum to infinite terms in GP.
General GP with infinite number of terms is of the following type
ar, ar2, ar3, ……….., arn-1 .........∞
Sum to infinite terms of GP is given by

SELECTION OF TERMS IN G.P.
ThreetermsinG.P.are:ar,a,ar,herecommonratioisr
FourtermsinG.P.are:ar3,ar,ar,ar3,herecommonratioisr2FivetermsinG.P.are:ar2,ar,a,ar,ar2,herecommonratioisr
PROPERTIES OF GEOMETRIC PROGRESSION:-
1) If all the terms of G.P. be multiplied or divided by the sane non- zero constant, then it remains a G.P. with common ratio r.
2) Reciprocal of the terms of a G.P. form a G.P.
3) If each term of a G.P. raised to the same power , the resulting sequence also form a G.P.
4)Ifa1,a2,a3,........an....arethetermsofG.P.,thenloga1,loga2,.....logan...........areinA.P.andvice−versa
GEOMETRIC MEAN
If a, b, c are the three terms of GP then b is said to be the Geometric Mean and is given byb=√acorb2=ac
Explanation:-
If a, b, c are in GP thenba=r=cb ⇒ ba=cbb2=ac⇒b=√ac
Componendo and Dividendo
If four terms a, b, c, d are proportional then ab=cd
When we apply componendo and dividendo then we get a+ba−b=c+dc−d
orNumerator+DenomenatorNumerator−Denomenator=Numerator+DenomenatorNumerator−Denomenator
SPECIAL RESULTS:-
Sum of first n natural number is given by
}{2})
Sum of square of first n natural number is given by
(2n+1)}{6})
Sum of cube of first n natural number is
}{2}%20\right%20]^{2})
Question:
The first term of an infinite G.P. is 1 and any term is equal to the sum of all terms that follow it. Find the infinite G.P.
Solution: It is given that: a = 1
A.T.Q. Tn = Tn+1 + Tn+2 + Tn+3 + ……………………
arn-1 = arn + arn+1 + arn+2 + ……………………
arn−1=arn1−rNow cross multiply it and putting a = 1 we get rn−1−rn=rn⇒2rn=rn−1⇒2r=1⇒r=12
Putting a = 1 and r = 1/2 we get the required sequence as follows 12,14,116,.......,∞
THANKS FOR YOUR VISIT
PLEASE COMMENT BELOW