Basic Proportionality Theorem Class 10th
(OR) B.P.T. or Thales Theorem
Converse of basic proportionality theorem, thales theorem 10th standard, theorem 6.2 class 10
Statement:-
If a line is drawn parallel to one
side of the triangle to intersect the other two sides in two distinct points, the other two sides are divided in the same ratio.
Given:-
A Δ ABC in which line l ॥ BC, intersect side AB and AC at point D and E
To Prove :-
Construction :-
Draw EM 丄 AB and DN 丄 AC. Also join
BE and CD
Proof :- Area of triangle = ✕ Base ✕ Height
Area of △ ADE = ✕ AD ✕ EM ..............(1)
Area of △ BDE = ✕ BD ✕ EM ..............(2)
Divide equation (1) by equation (2) we get
Similarly
ΔBED and ΔCDE are two triangles on the same base and lie
between the same parallel DE and BC
∴ Ar(ΔBED) = Ar(ΔCDE)
.................. (5)
From equation (3), (4), (5) we get
Hence prove the Basic Proportionality Theorem.
Note:- For the examination point of view students should study the basic proportionality theorem only its converse is only a motivational theorem.
Converse of Basic Proportionality Theorem
If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side.
Given:- In Triangle ABC,
To Prove :- Line DE॥ BC
Construction:-
If DE is not parallel to BC, then let us take another line DE'॥ BC
Proof:-
In ΔABC, DE'॥ BC Therefore by B.P.T
Therefore
Adding 1 on both side
This is possible only if E and E' coincide with each other
⇒ E and E' represent the same point on the side of the triangle.
Hence DE is parallel to the side BC
Converse of BPT is proved
Important result based on BPT
If a line intersects side AB and AC of a ΔABC at D and E respectively and is parallel to BC, then prove that
Solution :-
It is given that DE॥BC, therefore by BPT
......... (∵ By Invertendo
Adding 1 on both side we get
.......... ( ∵ By Invertendo
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