Math Assignment Class X Ch-4 | Quadratic Equations

Math Assignment Class X
Chapter 4 Quadratic Equations

Extra questions of chapter 4 class 10 Quadratic Equations with answer and  hints to the difficult questions. Important and useful math assignment for the students of class 10

ASSIGNMENT FOR 10 STANDARD QUADRATIC EQUATIONS

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Question 1. Check whether the given values of x are the solution of equation or not.

a) x2√2x – 4 = 0  : At  x = √2, x = -2√2   : Ans [yes]        

b) (2x + 3)(3x - 2) = 0  : At  x = 2/3             : Ans [yes]

c) 6x2 – x – 1 = 0    : At x = 1/2,  x = 3/2                    

Ans  [At x=1/2  yes, at x= 3/2  no]

Question 2. Find k if the value of x is the solution of Q. E.

a)  3x2 - 2kx + 5 = 0      : At   x = 2                  

Ans  [k = 17/4]      

b)  x- (a + b)x + k = 0    : At  x = a                        

Ans [ k = ab ]                 

c) kx√3x + 6 = 0    : At x = √3                              

Ans [ k = - 3]

Question 3. If x = - 2 and x = -1/5 are the solution of  5x2 + k x + p = 0 then find k and p.

Ans [K = 11, P = 2]

Question 4. Check whether 3 is the root of this equation. 

equation

Ans [yes]
Question 5. Solve the following by factorisation method

a) y2 - 5 = 0                          [Ans ± √5                 

b) (2x + 3)2 = 81                  [Ans  -6 & 3]

c) ax- 2bx = 0                    [Ans 0, 2b/a]                

d) 4√5x2 + 7x - 3√5 = 0       [Ans -3/√5√5/4]

e) 5x- 17/2 x + 3/2 = 0     [Ans [3/2, 1/5]            

f) 3a2x2 + 8abx + 4b= 0   [Ans -2b/a,  -2b/3a]

g) a2b2x2 + b2x - a2x – 1 = 0     [Ans 1/b2, -1/a2       

h) ax2 + (4a2 - 3b)x - 12ab = 0   [Ans -4a, 3b/a]

i).  equation      [Ans 5, 5/2]                    

j).  ab - x2 = (a - b)x                  [Ans -a, b]

Question 6. If - 4 is a root of the equation x2 + px – 4 = 0 and the equation x2 + p x + k = 0 has equal roots. Find k. 

Ans [k = 9/4  ]

Question 7. If one root of the equation   x2 – k x - 2  = 0 is 2  then find k and other root.   

Ans [k = 3,  other root -1].

Question 8. Find the value of m for which the roots of the equation mx(6x + 10) + 25 = 0  are equal.
Ans [m = 6]

Question 9. Discuss the nature of the roots of the following

a) 9x2 - 12x + 4 = 0             b) x2 – 3 x  = 0  

c) x2 -  1/3x  +3/4 = 0         d) x2 - 22x - 2√3 = 0                                    

e) √3x2 - 22x - 2√3 = 0     f) 2x2 √5x + 3 = 0

Question 10. Find the quadratic equation whose roots are

a) -8 &  -3      [Ans  x2 + 11x + 24 = 0 ]                  

b)  1 + √2 and 1 - √2      [Ans  x2 - 2x - 1 = 0 ]

c)  equation    [Ans 4x2 - 16x + 11  =  0 ]

Question 11. For what value of p will the following equation have real roots

a) 9x2 - 5x + (p + 1) = 0    [Ans  p  ≤ -11/36]  

b) 2x2 – p x – 4 = 0          [Ans  No Value of P]

Question 12. For what value of k the equations have real and repeated roots(or equal roots)

a) (3k + 1)x2 + 2(k + 1)x + k = 0    [ Ans  K = -1/2, 1]               

b) x2 - 2(k + 1)x + k2 = 0                 [Ans  k = -1/2]

c) 4x2 - 2(k + 1) + k + 4 = 0            [Ans k = 5, k = - 3]                 

d) 9x2 + 8kx + 16 =0                      [Ans  k= ±3]

e) (k-12)x2 + 2(k - 12)x + 2 = 0     [Ans k = 12]                       

f) (k + 4)x2 + (k +1)x + 1 = 0        [Ans   k = 5, -3]

Question 13. Find the roots of the following by using quadratic formula.

a) 3x2 + 25x – 5 = 0        Ans [√5/3, √5]               

b) p2x2  +  (p-  q2)x  -  q2 = 0   : Ans [q2/p2, -1]

c) 12abx- (9a-  8b2)x - 6ab = 0   : Ans [3a/4b,  -2b/3a]

d) (a + b) 2x2 + 8(a2 - b2)x + 16(a - b)= 0     [Ans  equationequation

e) 4x2 - 4a2x + (a4 - b4) = 0        Ans  equation 

f) 9x2 - 9(a + b)x + 2a2 + 5ab + 2b2 = 0     Ans  equation

g) 4x2 - 2(a2 + b2)x + a2b2  = 0    Ans [a2/2 ,  b2/2]          

h) equation         [Ans 1/-4]

i) 3y2 + (6 + 4a)y + 8a = 0       Ans [-2, - 4a/3]              

 j)  (a + b)2x2 + 8(a2 - b2)x + 16(a - b)2 = 0   :  Ans  equation

Question 14. If 𝞪 and 𝞫 are the roots of the quadratic equation ax2 + bx + c = 0, then find the value of:

a) 𝞪2 + 𝞫2         [Ans  equation         

Hint: Using the identity :  a2 +b2 = (a + b)2 – 2ab                                        

 b) 𝞪3 + 𝞫3       Ans equation    

Hint : Using the identity : a3 + b3 = (a + b)3 - 3ab(a + b)                                               

c)    equation         Ans equation 

Question 15. If  and  are the roots of  2x2 + 5x – 4 = 0 then find the value of

a)  𝞪2 + 𝞫2   - 4 𝞪𝞫          Ans [73/4]

b) 𝞪3 + 𝞫3                              Ans[-245/8]

Question 16. Solve: a) √x + 2x =1     Ans (1, 1/4)                               

b)  equation + x = 13   : Ans (20, 8)

Hint: Bring all terms without square root to the RHS. Squaring on both side to get a QE and then solve it.

Question 17. Solve the following for the value of x  : equation

Ans : x = - a, - b 

Hint:  Bring 1/x to the LHS

Now taking LCM and solving the QE for the value of x

Question 18. Solve: (a) equation   

Ans  (-4, - 4/7)           

Solution Hint:  Puttingequation  and  equation  and find the QE in terms of y

Solve the QE and find the value of y. Find the value of y the replace y into x. Again solve the equation for the value of x.

Question 19. Two pipes running together can fill a tank in equation minutes. If one pipe takes 1 minute  more than the other to fill the tank. Find the time taken by each pipe. 
[Ans 5 &  6 minutes ]

Question 20. Rs.6500 were divided equally among a certain no. of persons. Had there been 15 more persons, each would have got 30 less. Find the no. of persons.

Question 21. A peacock is sitting on the top of the pillar, which is 9m high. From a point 27m away from the bottom of the pillar, a snake is coming to its hole at the base of the pillar. Seeing the snake, the peacock pounces on it. If their speeds are equal, at what distance from the hole is snake caught.       
Ans [12m  

Question 22. The side of square exceeds the side of another square by 4cm and the sum of their areas is 400cm2. Find the sides of two squares.                     
Ans   [16cm & 12cm ]      

Question 23. The difference of two numbers is 4. If the difference of their reciprocals is .   Find two numbers.     
 Ans [3, 7] 

Question 24. A motor boat whose speed in still water is 5km/h, takes 1 hour more 12 km upstream than to downstream to the same spot. Find the speed of the stream.             
Ans [1km/h],

Question 25. If -5 is the root of the quadratic equation 2x2 + px – 15 = 0 and p(x2 + x) + k = 0 has equal roots then find the value of p and k.
Ans [p = 7 & k = 7/4 ]

Question 26. Divide 12 into 2 parts such that the sum of their squares is 74.                
Ans  [7, 5]

Question 27. A year ago, the father was 8 times as old as his son. Now his age is the square of his son’s age. Find their present ages.    
Ans [7, 49]

Question 28. The speed of the boat in still water is 8km/h. It can go 15km upstream and 22km downstream in 5hrs. Find the speed of stream.    
Ans  [3km/h]

Question 29. Side of a square exceeds the side of another square by 4cm. And the sum of the areas of the two squares is 400cm2. Find the dimensions of the square.      
Ans [12, 16]

Higher Order Thinking Skill
HOTS
Question 30. 
Solve: a)   equation              

Ans (1, 2, 1/2)
Solution Hint:  

Putting equation  then squaring on both sides and find the value ofequation 

 Now find and solve the QE in terms of y

Now replacing the value of y in terms of x

Solve b)   equation               

Ans (-1/2, 2, -1/4, 4)

Solution Hint:  

Putting  equation then squaring on both sides and find the value of  equation 

 Now find and solve the QE in terms of y

Now replacing the value of y in terms of x

Question 31. 
Out of a number of Saras birds, (1/4)th of the number are moving about in Lotus plants, (1/9)th coupled with (1/4)th as well as 7 times the square root of the number move on a hill, 56 birds remain on the trees.   What is the total no. of words.          
Ans   [576] 

Solution 31

Let total birds = x

No. of birds moving in lotus plant = (1/4)x

No. of birds coupled with = (1/9 +1/4)x = (13/36)x

No of birds moving on the hill = 7x

No. of birds on the tree = 56

Acoording to the question

equation

equation

equation

equation

equation

equation

equation

Putting equation

equation

equation

equation

equation

equation

equation

equation

Hence Total Number of birds = 576

Question 32.
7 years ago, age of Varun was five times the square of the age of Swati. After 3 years, age of Swati will be 2/5 of the age of Varun. Find their present ages.

Solution :

Let 7 years ago the age of Swati = x years

Let 7 years ago the age of Varun = y years

ATQ       y = 5x2 …………………(1)

Present age of Swati = x + 7

Present age of Varun = y + 5

After 3 years age of Swati = x + 10

After 3 years age of Varun= y + 10

Again ATQ :  Age of Swati = (2/5) age of Varun

x + 10 = (2/5)[y + 10]

5(x + 10) = 2y + 20

5x + 50 = 2y + 20

Putting  y = 5x2  we get

5x + 50 = 2(5x2 ) + 20

10x2  - 5x + 20 - 50 = 0

10x2 - 5x - 30 = 0

2x2 - x - 6 = 0    (Dividing by 5)

(2x + 3)(x - 2) = 0

x = - 3/2 (Rejected)     and   x = 2

Putting x = 2 in equation (1) we get

y = 5 (2)2    ⇒     y = 20

Present age of Swati = x + 7  = 2 + 7 = 9

Present age of Varun = y + 7 =  20 + 7 = 27

THANKS FOR YOUR VISIT 
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